# Session Objectives

At the end of this chapter, candidates should be able to use the product formulae to solve trigonometric problems.

If you have any question regarding our last Class kindly don’t hesitate to ask

# Product Formulae

## First Expression

Recall that from the addition formulae,

sin (A + B) = sinAcosB + cosAsinB

And

sin (A − B) = sinAcosB − cosAsinB

Adding the two expressions together will give us;

sin (A + B) = sinAcosB + cosAsinB

+

sin (A − B) = sinAcosB − cosAsinB

sin (A + B) + sin (A − B) = sinAcosB + cosAsinB + sinAcosB − cosAsinB

sin (A + B) + sin (A − B) = 2sinAcosB

## Second Expression

sin (A + B) = sinAcosB + cosAsinB

And

sin (A − B) = sinAcosB − cosAsinB

Subtracting the two expressions will give us;

sin (A + B) = sinAcosB + cosAsinB

−

sin (A − B) = sinAcosB − cosAsinB

sin (A + B) − sin (A − B) = sinAcosB + cosAsinB − (sinAcosB − cosAsinB)

sin (A + B) − sin (A − B) = sinAcosB + cosAsinB − sinAcosB + cosAsinB

sin (A + B) − sin (A − B) = 2cosAsinB

Let

X = 2sinAcosB,

Y = 2cosAsinB

P = sin (A + B)

Q = sin (A − B)

Hence,

X = P + Q and,

Y = P − Q

X + Y = P + Q + P − Q

X + Y = 2P

Make **P** the subject of the formula;

X + Y = 2Ptop↑

X = P + Q

Y = P − Q

X − Y = P + Q − (P − Q)

X − Y = P + Q − P + Q

X − Y = 2Q

Make

**Q**the subject of the formula;

sin (A + B) + sin (A − B) = 2sinAcosB

And

sinX + sin Y = ½(2sin P + Qcos P − Q)

Recall that from the second expression;

sin (A + B) − sin (A − B) = 2cosAsinB top↑

And

sinX − sin Y = ½(2cos P + Qsin P − Q)

Also,

cos (A + B) = cosAcosB − sinAsinB

And,

cos (A − B) = cosAcosB + sinAsinB

If we put X = P + Q, and Y = P − Q

then,

Hence,

cos X + cos Y = ½(2cos P + Qcos P − Q)

cos X − cos Y = ½(2sin P + Q sin P − Q)

All the above formulae that we just expressed are called **Product Formulae**

Now let look at 2 or more examples,

# Examples Of Product Of Two Trigonometric Ratio

## Example 1

Express sin 4x + sin 2x and sin 8x − sin 2x as product of two trigonometric ratios.

### Solution 1

To solve this question, you don’t need any calculations just follow the expressions that will have analyse above and input the parameters.top↑

sin 4x + sin 2x = ½(2sin 4x + 2x cos 4x − 2x)

= 2sin 3x cos x

### Solution 2

Also use the same procedure

sin 8x − sin 2x = ½ (2cos8x + 2x sin 8x − 2x)

= 2cos 5x sin 3x

## Example 2

Express cos 6x + cos 4x and cos 4x − cos 2x as product of two trigonometric ratios.

### Solution 3

cos 6x + cos 4x = ½( 2cos 6x + 4xcos 6x − 4x)

= 2cos 5x cos x

### Solution 4

cos 4x − cos 2x = ½(−2sin 4x + 2xsin 4x − 2x)

−2sin 3x sin x

# Examples Of Sum Of Two Trigonometric Ratio

## Example 1

Express sin 5xcos 3x as a sum of two trigonometric ratio.top↑

### Solution

Recall,

sinX + sinY = ½(2sin X + Ycos X − Y)

Agree that

½[sinX + sinY] = ½(sin X + Ycos X − Y)

Put

And

then cross multiply,

X + Y = 5x × 2

X + Y = 10x……. eqn (1)

X − Y = 3x × 2

X − Y = 6x…….. eqn (2)

Solving the two equation simultaneously

X + Y = 10x

X − Y = 6xtop↑

Making **X** the subject of the formula in equation 2

X − Y = 6x

X = 6x + Y

Put **X = 6x + Y** into equation 1

X + Y = 10x

(6x + Y) + Y = 10x

6x + 2Y = 10x

2Y = 10x − 6x

2Y = 4x

Y = 2x

Put **Y = 2x** into equation 2

X − Y = 6x

X − (2x) = 6x

X − 2x = 6x

X = 6x + 2x

X = 8x

So if X = 8x and Y = 2x then,

sin 5xcos 3x = ½[sin 8x + sin 2x]

## Example 2 Express cos 7xsin 5x as a sum of two trigonometric ratio.

### Solution

Similar to the first example,

cos 7xsin 5x = ½[sinX − sinY]top↑

Put

And

then cross multiply,

X + Y = 7x × 2

X + Y = 14x…… eqn (1)

X − Y = 5x × 2

X − Y = 10x …….. eqn (2)

Solving the two equations simultaneously,

X + Y = 14x

X − Y = 10x

Making X the subject of the formula in equation 1

X + Y = 14x

X = 14x − Y

Put **X = 14x − Y** into equation 2

X − Y = 10x

(14x − Y) − Y = 10x

14x − Y − Y = 10x

14x − 2 Y = 10x

−2Y = 10x − 14x

−2Y = − 4x

Y = 2xtop↑

Put **Y = 2x ** into equation 1

X + Y = 14x

X + (2x) = 14x

X + 2x = 14x

X = 14x − 2x

X = 12x

So if X = 12x and Y = 2x then,

cos 7xsin 5x = ½[sin 12x − sin2x]

## Example 3

Express cos 9xcos 3x as a sum of two trigonometric ratio.

### Solution

Same procedure,

cos 9xcos 3x = ½[cosX + cosY]

Put

And

then cross multiply,

X + Y = 9x × 2

X + Y = 14x……. eqn (1)

X − Y = 3x × 2

X − Y = 6x…….. eqn (2)

Solving the two equations simultaneously

X + Y = 14x

X − Y = 6x

Make **X or Y** the subject of the formula in any of the equation. (Your choice)

Making **X** the subject of the formula in equation 2top↑

X − Y = 6x

X = 6x + Y

Put **X = 6x + Y** into equation 1

X + Y = 14x

(6x + Y) + Y = 14x

6x + Y + Y = 14x

6x + 2Y = 14x

2Y = 14x − 6x

2Y = 12x

Y = 6x

Put **Y = 6x** into equation 2

X − Y = 6x

X − (6x) = 6x

X − 6x = 6x

X = 6x + 6x

X = 12x

So if X = 12x and Y = 6x then,

cos 9x cos 3x = ½[cos 12x + cos 6x]

# Question Of The Day

Express sin 3xsinx as a sum of two trigonometric ratio? Submit your answer through the comment box.

# Jokes Of The Day

I can’t stop laughing when I saw this picture, lol, it is true tho…

Is this true?top↑

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